try this..
SELECT DISTINCT AA FROM AA A WHERE STATUS='F' AND
AA IN (SELECT AA FROM AA B WHERE A.AA=B.AA AND STATUS <> 'F'
GROUP BY B.AA HAVING COUNT(B.AA) > 1)
Ramana
>
>--- Leslie Lu <[EMAIL PROTECTED]> wrote:
>> Just to clearfy my previous question (as follow):
>>
>> if 1 has F and A and B, that what I want.
>>
>> If 1 has F all the time, that's not what I want.
>> If 1 has A, B, C, but never F, that's not what I
>> want
>> either.
>>
>> --- Leslie Lu <[EMAIL PROTECTED]> wrote:
>> > Hi,
>> >
>> > If I have this:
>> > Customer_id Status
>> > ---------- -----------
>> > 1 F
>> > 1 A
>> > 1 B
>> > 2 F
>> > 2 F
>> > 3 A
>> > 3 B
>> >
>> > How do I found out a customer who has both F and
>> not
>> > F
>> > for them. (If he only gets F, or gets other than
>> F,
>> > that's fine). In this case, I should get 1.
>> Thank
>> > you! I need this badly!
>> >
>> > __________________________________________________
>> > Do You Yahoo!?
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>> >
>>
>>
>> __________________________________________________
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>> http://personal.mail.yahoo.com/
>>
>
>
>__________________________________________________
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>--
>Please see the official ORACLE-L FAQ: http://www.orafaq.com
>--
>Author: Leslie Lu
> INET: [EMAIL PROTECTED]
>
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--
Please see the official ORACLE-L FAQ: http://www.orafaq.com
--
Author: Ramana
INET: [EMAIL PROTECTED]
Fat City Network Services -- (858) 538-5051 FAX: (858) 538-5051
San Diego, California -- Public Internet access / Mailing Lists
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