Ethan,
Try this:
-- LeftMost bin:
SUM(DECODE(SIGN(lim_val0 - column_value),1,1,0,1,0)) -- less then
lim_val0
-- Middle bins:
SUM(DECODE(DECODE(SIGN(lim_val1 - column_value),-1,0,1), 1 ,
DECODE(SIGN(lim_val0 - column_value),-1,1,0), 0)) -- for
(lim_val1-lim_val0) bin
SUM(DECODE(DECODE(SIGN(lim_val2 - column_value),-1,0,1), 1 ,
DECODE(SIGN(lim_val1 - column_value),-1,1,0), 0)) -- for
(lim_val2-lim_val1) bin
SUM(DECODE(DECODE(SIGN(lim_val3 - column_value),-1,0,1), 1 ,
DECODE(SIGN(lim_val2 - column_value),-1,1,0), 0)) -- for
(lim_val3-lim_val2) bin
...................
.....................
-- RightMost bin:
SUM(DECODE(SIGN(lim_valN - column_value),1,0,0,0,1)) -- greater then
lim_valN
Igor Neyman, OCP DBA
Perceptron, Inc.
(734)414-4627
[EMAIL PROTECTED]
----- Original Message -----
To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
Sent: Tuesday, July 24, 2001 1:28 PM
> Anyone got a good example of flipping a range of values into columner
> buckets. I have done this in the past but my solutions always seem so
> convoluted, it seems I have seen more elegant examples in the past. I
want
> to use decode so it will run on older versions of Oracle.
>
> Pseudo Example:
>
> select
> sum(decode(if value between 0 and 64 then return 1 else 0))
> count_of_this_bucket,
> sum(decode(if value between 65 and 128 then return 1 else 0))
> count_of_this_bucket,...
> from
> table
>
> Thanks,
> Ethan
>
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