Seema:
Here's my crack at it:
select x.userid
, x.superid
, nvl(y.count, 0) as count
from mytable x
, (select a.userid
, a.superid
, count(*) as count
from mytable a
, mytable b
where a.userid=b.superid
group by a.userid, a.superid) y
where x.userid = y.userid(+)
order by 1, 2;
Jon Walthour
>
> From: "Seema Singh" <[EMAIL PROTECTED]>
> Date: 2001/08/22 Wed AM 09:00:28 EDT
> To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
> Subject: sql query
>
> Hi
> One table has following information
> userid superid
> 14 -1
> 4 0
> 8 2
> 9 2
> 15 2
> 24 4
> 16 4
> 25 4
> 6 5
> 7 5
> 26 5
> 2 16
> 18 16
> 10 18
> 11 18
> 1 24
> 5 24
> 13 24
> I want the output in following format
> userid superid COUNT
> 14 -1 0
> 4 0 3
> 8 2 0
> 9 2 0
> 15 2 0
> 24 4 3
> 16 4 2
> 25 4 0
> 6 5 0
> 7 5 0
> 26 5 0
> 2 16 3
> 18 16 2
> 10 18 0
> 11 18 0
> 1 24 0
> 5 24 3
> 13 24 0
> Where userid =xx , select count where Superid=xx
> Please suggest the query.
> THANKS
> -Seema
>
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> Author: Seema Singh
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Author: Jon Walthour
INET: [EMAIL PROTECTED]
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