Hi,
You don't need to do arithmetic to find number of
rows in a block from block dumps. There will be a
component in block dump called 'numrow' or 'nrow'
which will tell how many rows are there in that block.
It will be something like that in case if you have
20 rows
nrow=20
Best Regards,
K Gopalakrishnan
Bangalore, INDIA
-----Original Message-----
bhatti
Sent: Tuesday, September 25, 2001 11:41 AM
To: Multiple recipients of list ORACLE-L
OK, so somebody asks me if there is a way to determine
how full an Oracle data block is. I've been playing
around with dbms_space and dbms_rowid packages but
apparently, I can't see how these would help. A
couple interesting scripts both on ixora and Jonathan
Lewis web site seem to have helped. I used JL's
script 'alter system dump datafile <df_no> block min
<min_blk> block max <max_blk>;' to dump the segment
header and block headers for various data blocks.
For example, if I run this:
alter system dump datafile 122 block min 4 block max
4, I dump the header info for block 4 in datafile 122.
Question is, when I look in the trace file I see the
following line:
block_row_dump
tab 0, row 53, @0x46c
tl: 2 fb: --HDFL-- lb:0x1
...
...
tab 0, row 98, @0x1f21
tl: 2 fb: --HDFL-- lb: 0x1
end_of_block_dump
So, am I correct in assuming that there are 46 rows
(98-53+1=46) in this block? If this is the case, I
would be able to calculate the average row size for
this block and do all sorts of silly little 'rithmetic
calculations based on pctfree etc. This would give
fairly granular insight into how tightly packed blocks
are, right?
Any opinions?
tia
mkb
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