or (sysdate - 18/24)

> -----Original Message-----
> From: Mercadante, Thomas F [mailto:[EMAIL PROTECTED]]
> Sent: Tuesday, April 09, 2002 9:08 AM
> To: Multiple recipients of list ORACLE-L
> Subject: RE: SQL : where clause to include data for the previous 24
> hours
> 
> 
> Johan,
> 
> There is no need to convert sysdate to a string and back to a 
> data.  I'm not
> sure what you mean by  "calculate the previous 24 hours when 
> a query is run
> and bump the time by 6 hours".
> 
> It looks like you are trying to retrieve all records that 
> have a date/time
> within the last 18 hours - is this correct?  if so, then your 
> query would
> be:
> 
> where event_date > (sysdate + 6/24) - 1
> 
> The default date format really has nothing to do with how the 
> dates are
> stored within the database - they are all stored the same 
> way.  This means
> you can do simple date math like above.
> 
> Hope this is what you are looking for.
> 
> Tom Mercadante
> Oracle Certified Professional
> 
> 
> -----Original Message-----
> Sent: Tuesday, April 09, 2002 8:13 AM
> To: Multiple recipients of list ORACLE-L
> 
> 
> I need a where clause to ACCURATELY (down to the second) calculate the
> previous 24 hours when a query is run and bump the time by 6 hours
> (event_date is based on GMT). The default date format has been set to
> 'SYYYY-MM-DD HH24:MI:SS','NLS_CALENDAR=GREGORIAN'.
> 
> I've tried the following:
> 
> " where event_date > 
> (to_date(substr(sysdate,0,22),'YYYY/MM/DD HH24:MI:SS')
> + 6/24) - 1".
> 
> Any ideas?
> 
> -- 
> Please see the official ORACLE-L FAQ: http://www.orafaq.com
> -- 
> Author: Johan Muller
>   INET: [EMAIL PROTECTED]
> 
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> Author: Mercadante, Thomas F
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