Try this
SELECT COUNT(*)
from leisure_plan_master_temp
where membership_class = 'D'
AND (PAY_METHOD IS NULL or pay_METHOD NOT IN ('C','P')) ;
-----Original Message-----
Sent: Monday, May 06, 2002 12:18 PM
To: Multiple recipients of list ORACLE-L
Hello Lisa,
Null values are excluded from search list for "in" statement.
Saturday, May 04, 2002, 6:43:38 AM, you wrote:
KL> Slap me if this is a dumb question.
KL> Here's my pay methods
SQL>> SELECT ASCII(PAY_METHOD), PAY_METHOD, COUNT(*)
KL> 2 FROM LEISURE_PLAN_MASTER_TEMP
KL> 3 WHERE MEMBERSHIP_CLASS = 'D'
KL> 4 GROUP BY PAY_METHOD;
KL> ASCII(PAY_METHOD) P COUNT(*)
KL> ----------------- - ----------
KL> 67 C 42955
KL> 80 P 34373
KL> 11786
KL> I expected this statement to return the 11,786 records that have null
KL> values. However, it doesn't:
SQL>> SELECT COUNT(*)
KL> 2 from leisure_plan_master_temp
KL> 3 where membership_class = 'D'
KL> 4 AND pay_METHOD NOT IN ('C','P');
KL> COUNT(*)
KL> ----------
KL> 0
KL> But when I do this, I get the answer I expect.
SQL>> SELECT COUNT(*)
KL> 2 from leisure_plan_master_temp
KL> 3 where membership_class = 'D'
KL> 4 AND PAY_METHOD IS NULL;
KL> COUNT(*)
KL> ----------
KL> 11786
KL> This isn't exactly correct. There may be other values in this field,
and if
KL> they show up I need to include them, not just records where this field
is
KL> null. What am I missing? Is it because the value is NULL that Oracle
KL> excludes it from the IN() statement, because of the classic definition
of
KL> NULL (can't be defined, therefore can't be sure it's not a C or a P)?
KL> This is easy enough to fix, I'll change my data load to populate the
null
KL> values with my own code. But still? Have I got the WHY correct?
KL> Thanks for any light someone can shed on this stupid question.
KL> Lisa Koivu
KL> Oracle Database Monkey Mama
KL> Fairfield Resorts, Inc.
KL> 5259 Coconut Creek Parkway
KL> Ft. Lauderdale, FL, USA 33063
--
Best regards,
Sergey mailto:[EMAIL PROTECTED]
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