DIR=<directory where the files live>
ls $DIR |
while read FILE
do
sqlldr ... file=$DIR/$FILE ...
done
--- Ravindra <[EMAIL PROTECTED]> wrote:
> We have a process that generates log file
> continously with dateandtime stamp on the filename
> like log_041502_113545.log
>
> These log files should be loade to the table using
> sql loader.I have the sqlldr script to load to
> the table.But this sqlldr will be part of the shell
> script that is will be executed as cron job
> on the unix server.
>
> How can I read the varying file name in the sqlldr
> command and automate the sqlldr job.
>
> thanks
> Ravi
>
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