Try this
select a.f1, a.d1, a.d2
from
(select field1 f1,date1 d1,max(date2) d2 from temp group by field1,date1)
a,
(select field1 f1,date1 d1,max(date2) d2 from temp group by field1,date1)
b
where a.f1 = b.f1
and a.d1 < b.d1
and a.d2 > b.d2
-----Original Message-----
Sent: Friday, May 31, 2002 10:59 AM
To: Multiple recipients of list ORACLE-L
Hi,
I have a table with 1 field and 2 dates: field1, date1, date2. I need to
find the max value of date2 for all the field1, date1 combinations. Then I
want to join the table to itself on field1 and find all the rows where
field1 matches, date1 < date1, and max(date2) > max(date2). I did this in 2
queries. First I created a view as follows:
create view v1 (f1, d1, d2)
as select field1,date1,max(date2) from table1
group by field1,date1;
Then I joined the 2 views together like this:
select a.f1,a.d1,a.d2 from v1 a, v1 b
where a.f1 = b.f1
and a.d1 < b.d1
and a.d2 > b.d2;
This worked fine, but I was wondering if there was a way to do this in
one query without having to create a view.
Bill Carle
AT&T
Database Administrator
816-995-3922
[EMAIL PROTECTED]
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Author: Carle, William T (Bill), ALCAS
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