Why do you need the to_char?
But wouldn't it work anyway with
to_char(a.updated_date,'dd/mm/yyyy hh24:mi:ss') =
( select to_char(max(updated_date),'dd/mm/yyyy hh24:mi:ss'))
which will also use the 24 hour clock instead of
to_char(a.updated_date,'dd/mm/yyyy hh:mi:ss') =
( select max(to_char(updated_date,'dd/mm/yyyy hh:mi:ss'))
Iain Nicoll
-----Original Message-----
Sent: Wednesday, August 14, 2002 5:54 PM
To: Multiple recipients of list ORACLE-L
Hi All,
I am using the to_char function in the following query. But it treats the
date '31/12/2001' as greater than '01/01/2002'.
Is there any solution to fix this problem?
select distinct(a.default_type_id), a.new_val
from amend_default_value a, amend_default_value b
where a.effective_from <= sysdate and
a.effective_to >= sysdate and
a.group_id = '942' and
a.default_type_id = b.default_type_id and
to_char(a.updated_date,'dd/mm/yyyy hh:mi:ss') =
( select max(to_char(updated_date,'dd/mm/yyyy hh:mi:ss'))
from amend_default_value c
where c.effective_from <= sysdate and
c.effective_to >= sysdate and
c.group_id = '942' and
c.default_type_id = b.default_type_id);
Thanks in advance.
regards,
Karthik
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