Aleem,
Your query should be:
SELECT year_date, to_char(attend_date, 'hh:mi:ss' )
FROM A, B
WHERE to_char(year_date, 'dd-mm-yyyy')
= to_char(attend_date,'dd-mm-yyyy') (+)
The above says to return all records from the year_date table and , oh, by
the way, return any records in the employee table where dates match.
A better way to do this would be:
WHERE trunc(year_date) = trunc(attend_date) (+)
The Trunc command simply strips all time from date columns.
Hope this helps
Tom Mercadante
Oracle Certified Professional
-----Original Message-----
Sent: Thursday, August 22, 2002 8:38 AM
To: Multiple recipients of list ORACLE-L
Hi,
In our employee's attendance application the attendance data is stored in
table 'A' including employee ID and attendance date & time. Another table
'B' has one column with dates of current year (365 records). For the sake of
simplicity, other fields are ignored.
Table: A
Employee_ID
Attend_date (date with time)
Table: B
year_date (one record each for a day of current year i.e., 365 records)
In a report (single employee at a time) showing all dates of the year and in
front of it whether the employee was present or not we are running the
following query. Assume that table A has 15 records of employee ID 123, the
query should return 365 records with 15 records telling the time but it
returns 15 records only.
SELECT year_date, to_char(attend_date, 'hh:mi:ss' )
FROM A, B
WHERE to_char(year_date, 'dd-mm-yyyy') = to_char(attend_date(+),
'dd-mm-yyyy') and employee_id = 123;
To my understanding this is perhaps because of the filter employee_ID=123.
What would be the query to get the required result?
TIA!
Aleem
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