Well it works but your query assumes knowledge of the tree- that it will
always only have 3 levels. Consider when I add the following 2 rows:
insert into treenode values(10,3,1,'nested folder2.2.1');
insert into treenode values(11,10,2,'nested folder2.2.2');
Now it fails. SORRY I wasn't clear on this part of the rules/spec. :-(
We should be able to add nodes and levels. We should also be able update
nodes to different parents and their children and children's children (etc)
should automatically following them around on the tree.
Any other ideas?
Steve
-----Original Message-----
Sent: Tuesday, November 05, 2002 12:20 PM
To: [EMAIL PROTECTED]
Cc: Orr, Steve
Importance: High
Steve,
This works for me.
Jared
====================================================================
col nodelevel noprint
col parent noprint
col child noprint
select
a.nodelevel
, a.id id
, a.parentid
, a.nodeorder
, a.description
, decode(c.children,null,'N','Y') parent
, decode(p.children,null,'Y','N') child
from (
select level nodelevel, id, parentid, nodeorder, description
from treenode
start with parentid=0
connect by prior id = parentid
) a,
(
select parentid, count(*) children
from treenode b
group by parentid
) c,
(
select parentid, count(*) children
from treenode d
group by parentid
) p
where a.id = c.parentid(+)
and a.id = p.parentid(+)
order by
decode(parent
-- is a parent
, 'Y', nodelevel * id
-- is a child
, 'N', nodelevel * parentid + nodeorder
)
/
"Orr, Steve" <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED]
11/05/2002 09:24 AM
Please respond to ORACLE-L
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
cc:
Subject: SQL Brain Teaser Challenge
Challenge: present SQL results hierarchically and sort the nodes. Use sort
column without changing data. Here's the DDL/DML to start:
create table treenode (
id number not null
constraint pk_treenode
primary key,
parentid number not null,
nodeorder number not null,
description varchar2(20) null);
insert into treenode values(1,0,0,'top folder');
insert into treenode values(9,1,0,'1st subfolder');
insert into treenode values(7,1,2,'3rd subfolder');
insert into treenode values(2,1,1,'2nd subfolder');
insert into treenode values(8,7,1,'folder 3 item 2');
insert into treenode values(6,2,3,'folder 2 item 3');
insert into treenode values(5,7,0,'folder 3 item 1');
insert into treenode values(3,2,2,'folder 2 item 2');
insert into treenode values(4,2,1,'folder 2 item 1');
-----------------------------------------------------
Here's the data presented hierachically without the desired sort:
select * from treenode
start with parentid=0 connect by prior id = parentid;
ID PARENTID NODEORDER DESCRIPTION
---------- ---------- ---------- --------------------
1 0 0 top folder
9 1 0 1st subfolder
7 1 2 3rd subfolder
8 7 1 folder 3 item 2
5 7 0 folder 3 item 1
2 1 1 2nd subfolder
6 2 3 folder 2 item 3
3 2 2 folder 2 item 2
4 2 1 folder 2 item 1
-----------------------------------------------------
Desired SQL statement results:
ID PARENTID NODEORDER DESCRIPTION
---------- ---------- ---------- --------------------
1 0 0 top folder
9 1 0 1st subfolder
2 1 1 2nd subfolder
4 2 1 folder 2 item 1
3 2 2 folder 2 item 2
6 2 3 folder 2 item 3
7 1 2 3rd subfolder
5 7 0 folder 3 item 1
8 7 1 folder 3 item 2
-----------------------------------------------------
Kudos to anyone who can figure out how to do this via SQL.
Steve Orr
Bozeman, Montana
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