A "MINUS" operator in SQL will find the differences between two queries.  To
find indexes that are not associated with constraints (PK, UK, or FK), you
could you the following:

        select table_owner, table_name, column_name, column_position from
dba_ind_columns
        minus
        select owner, table_name, column_name, position from
dba_cons_columns;

Of course, it wouldn't give you the name of the index, so you can make this
an inline view for a larger query to hit DBA_IND_COLUMNS again would...

----- Original Message -----
To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
Sent: Friday, November 22, 2002 3:03 PM


>
> I don't get it. "Do a minus"? Mr. Shao could you explain that please.
>
> RWB
>
>
>
>
> "Shao, Chunning" <[EMAIL PROTECTED]>@fatcity.com on 11/22/2002 02:49:15 PM
>
> Please respond to [EMAIL PROTECTED]
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>
>
> Sent by:  [EMAIL PROTECTED]
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>
> To:   Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]>
> cc:
>
>
> The following will give you all the indexes that belongs to a constraint
>
>  select distinct t.owner as table_owner, i.table_name, o.owner as
> index_owner, o.object_name as index_name,s.name as
> constraint_name,c.constraint_type  from sys.cdef$ cd,dba_objects o,sys.con
> $ s,dba_constraints c,dba_indexes i,  dba_tables t Where t.Table_Name =
> i.Table_Name and i.owner=o.owner  and i.index_name=o.object_name and
> c.constraint_name=s.name  and cd.Enabled = o.object_id and cd.con# =
s.con#
> and o.owner not in ('SYS','SYSTEM')
>
>
> do a minus will get what you want.
>
>
> -----Original Message-----
> Sent: Friday, November 22, 2002 1:40 PM
> To: Multiple recipients of list ORACLE-L
>
>
> I am trying to find out what indexes are in the database only for
> performance
> reasons and do not enforce a constraint.  What would be the query to do
> that?
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