SELECT to_date('01-01-1970','DD-MM-YYYY') + no_of_seconds / (24*60*60) from
dual;

Regards
Naveen
-----Original Message-----
Sent: Thursday, January 23, 2003 3:34 PM
To: Multiple recipients of list ORACLE-L


Hi all

One of the developers came to me. They are using a Genesys call logging
system.

It has apparently stored a date time in a number field as the number of
seconds since 1970 1 Jan 0:00

They need to know exactly what time this is.

I can not off hand remember that oracle got a conversion routine for this.

Anyone know of one, they prefer something already there compared to
something that I write.


I was thinking  figure out how many days the seconds represent, add this to
the date of 1 Jan 1970. then figure out what time of day the remainder
seconds are to determine the time of day ?


Ideas.

George
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