At the risk of stating the obvious, doing
it in Perl looks like this:
#!/usr/bin/perl
use Date::Format qw(time2str);
my $t = 1043447100; # for example
print time2str("%T %A %d %B %Y",
$t), "\n";
-----Original Message-----
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED]] On Behalf Of Post,
Ethan
Sent: Friday, January 24, 2003
3:30 PM
To: Multiple recipients of list
ORACLE-L
Subject: RE: unix time conversion
function
Kinda...you can
change the year to 1970 if you want, this also converts to minutes, not
seconds. It is a really ugly function but it seems to work. You
could always use perl.
function
f_minutes {
# Funky function I use to calculate the number of minutes since
2000
MIN_YEAR=$( date +"%Y" )
MIN_YEAR=$( expr ${MIN_YEAR} - 2000 )
MIN_YEAR=$( expr ${MIN_YEAR} \* 525600 )
MIN_DAYS=$( date +"%j" )
MIN_DAYS=$( expr "${MIN_DAYS}" - 1 )
MIN_DAYS=$( expr "${MIN_DAYS}" \* 1440 )
MIN_HOURS=$( date +"%H" )
MIN_HOURS=$( expr "${MIN_HOURS}" \* 60 )
MIN_MINS=$( date +"%M" )
MIN_TOTAL=$(( ${MIN_YEAR} + ${MIN_DAYS} + ${MIN_HOURS} +
${MIN_MINS} ))
print ${MIN_TOTAL}
}
-----Original Message-----
From: Adams, Matthew (GECP, MABG,
088130) [mailto:[EMAIL PROTECTED]]
Sent: Friday, January 24, 2003
1:14 PM
To: Multiple recipients of list
ORACLE-L
Subject: unix time conversion
function
Anybody
got a handy little function to
convert a standard unix
seconds-since-Jan-1970 epoch
time (stored as a number) to a
readable date?
It would
save me a lot of time not having to re-invent the
wheel.
Matt
----
Matt Adams - GE Appliances -
[EMAIL PROTECTED]
My computer beat me at chess, but I
won
when it came to kick boxing.
