Hello everyone,
I'm trying to awk through a text file and use that with a passed-in message to send email. Here's an example of my text file:
# DBA's on call
[EMAIL PROTECTED] # Lisa pager
[EMAIL PROTECTED] # Lisa email
Here's my awk statement, which works properly
awk '!/^#/ {print $1}' filename.txt
prints the first entry in each file and skips any lines starting with #.
So I put it in a loop. I don't quite understand all the syntax here, I'm pulling the exact syntax out of Steve Adams' database check script.
--
for PAGER in ${*-$(awk '!/^#/ {print $1}' dba_oncall.txt)}
do
print $PAGER
done
--
Works fine.
Now when I try to pass in a parameter in $1 (which I mean to be the email message), awk grabs it and the script no longer works. Like this
--
export FILE=$1
print File is $FILE
for PAGER in ${*-$(awk '!/^#/ {print $1}' dba_oncall.txt)};
do
print $PAGER
done
--
This prints the name of the file in both print statements, before and inside the loop. What am I doing wrong?
Also if anyone can explain in a nutshell what the ${} means (I think it means consider the results as a variable) and the * and - and $() means in the for/do loop syntax I would be grateful. I'm leafing through my ksh book but I think this is several specific functions all slapped together.
Thanks to anyone that can help pull my head out of the sand...
Lisa Koivu
Oracle Database Administrator
Fairfield Resorts, Inc.
5259 Coconut Creek Parkway
Ft. Lauderdale, FL, USA 33063
Office: 954-935-4117
Fax: 954-935-3639
Cell: 954-683-4459
