gmei wrote:
> 
> Hi:
> 
> Just after I sent my original message, it occured to me that I could use
> this to "optimize" the sql (gneid is the PK column of the table):
> 
> select count(A.geneid), count(B.geneid) into count1, count2
> from isi.nametag A , isi.nametag B where A.geneid=geneid1 and
> B.geneid=geneid2;
> 
> Guang
> 

Think harder. What happens when say geneid1 is not found ?

BTW this kind of existence test is quite often dispensable ...

-- 
Regards,

Stephane Faroult
Oriole Software
-- 
Please see the official ORACLE-L FAQ: http://www.orafaq.net
-- 
Author: Stephane Faroult
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