That's a good approach to dealing with duplicates - wrap it up in another
query with a group by clause to remove the duplicates. It looks like we've
got your query down from "never" to around 30 seconds. Also since the
analytical function is doing a window sort and you will then be doing
another sort to remove duplicates the sort_area_size will have an impact on
performance - althought 30 seconds is probably good enough to not worry
about fiddling with this.
Just out of curiousity - did my query also return the duplicates? To be
honest, I'm not sure if RANK returns the same value for duplicates or not.
I guess that's something I should look into although I barely use this type
of query.
Regards,
Mark.
"Carol Bristow"
<[EMAIL PROTECTED] To: Multiple recipients of list
ORACLE-L <[EMAIL PROTECTED]>
ra.com> cc:
Sent by: Subject: RE: How to put a TOP 1 in a
select
[EMAIL PROTECTED]
.com
12/06/2003 05:25
Please respond to
ORACLE-L
That's always going to happen with something like a rank (or min/max).
You'll need to add some additional criteria to tell Oracle which of the
multiple records that you want to see returned. And that will depend on
the business needs. For example, you might want the earlier date, so you
could make the top line
select a.item, a.location, min(a.trans_date), b.can_vta
and add the appropriate group by. Or you may want the latest date - only
you can decide that.
HTH,
Carol Bristow
DPRA Inc.
1300 N 17th St Suite 950
Rosslyn, VA 22209
Work: 703-841-8025
Fax: 703-524-9415
-----Original Message-----
Sent: Wednesday, June 11, 2003 2:50 PM
To: Multiple recipients of list ORACLE-L
I run the next instruction:
select a.item, a.location, a.trans_date, b.can_vta
from (
select item, location, trans_date,
rank() over (partition by item, location order by quantity)
the_rank
from ictrans a
where company = 2000 and trans_date between (current_date-14) and
current_date
and doc_type = 'IS' and reason_code = 'VTCL'
and substr(item,2,2) = '57') a
INNER JOIN
(
select item, location, sum(quantity) as can_vta
from ictrans
where company = 2000 and trans_date
between (current_date-14) and current_date
and doc_type = 'IS' and reason_code = 'VTCL'
and substr(item,2,2) = '57'
group by item, location
) b
on a.item=b.item and a.location=b.location and a.the_rank=1
Information:
item Date Location Quantity
=======================================
0570018 5/29/2003 12:00:00 AM TJU02 -4
0570018 5/31/2003 12:00:00 AM TJU02 -3
0570018 5/30/2003 12:00:00 AM TJU02 -2
0570018 6/2/2003 12:00:00 AM TJU02 -2
0570018 6/3/2003 12:00:00 AM TJU02 -2
0570018 6/1/2003 12:00:00 AM TJU02 -1
0570018 5/30/2003 12:00:00 AM TJU24 -6
0570018 6/1/2003 12:00:00 AM TJU24 -6
0570018 6/2/2003 12:00:00 AM TJU24 -5
0570018 6/3/2003 12:00:00 AM TJU24 -3
0570018 5/31/2003 12:00:00 AM TJU24 -2
0570018 6/9/2003 12:00:00 AM TJU31 -4
Results:
Item Date Location Quantity
==========================================
0570018 5/29/2003 12:00:00 AM TJU02 -14
0570018 6/1/2003 12:00:00 AM TJU24 -22
0570018 5/30/2003 12:00:00 AM TJU24 -22
0570018 6/9/2003 12:00:00 AM TJU31 -4
The problem is that when we have an item that sold two or more days
the same quantity and it is the biggest quantity it returns more that
one row per item.
This query is execute in 28 seconds
>>> [EMAIL PROTECTED] 06/10/03 09:24PM >>>
There may be different ways to write this query - otherwise you need
to
look at tuning this query. Four minutes for a single product in a 5
million row table doesn't sound really good but I guess it depends on
hardware.
Have a look at the explain plan for the query - you have a lot of
selection
criteria on the ICTRANS table. If one (or a group) of those criteria
is
very restrictive then index (and analyze) that column(s) to see the
performance gain.
I've had a go at writing this as an analytical query. The syntax may
be
incorrect since I don't have anything convenient to test it against.
There
may even be syntax errors - it was simply typed in without being
executed.
Good luck!!!
select a.item, a.location, a.trans_date, sum(b.quantity) from (
select item, location, trans_date
rank() over (partition by item, location order by quantity
desc)
the_rank
from ictrans
where company = 2000 and trans_date between (current_date-14) and
current_date
and doc_type = 'IS' and reason_code = 'VTCL'
and substr(item,2,2) = '57') a,
ictrans b
where a.the_rank = 1
and a.item = b.item
and a.location = b.location
and b.company = 2000 and b.trans_date between (current_date-14) and
current_date
and b.doc_type = 'IS' and b.reason_code = 'VTCL'
and substr(b.item,2,2) = '57')
"Teresita Castro"
<[EMAIL PROTECTED] To: Multiple
recipients of list ORACLE-L <[EMAIL PROTECTED]>
martmx.com> cc:
Sent by: Subject: RE: How to
put a TOP 1 in a select
[EMAIL PROTECTED]
om
11/06/2003 11:59
Please respond to
ORACLE-L
This is an example of the information.
I forgot to mention that in each company we have supermarkets called
in the
system Locations. So when I do this query I have to return per item
the
total of sales in the las two week, the day that we sale more per
supermarket
Item trans_date Quantity Location
========================================
0570004 5/29/2003 12:00:00 AM -1 TJU02
0570004 6/3/2003 12:00:00 AM -1 TJU24
0570004 6/9/2003 12:00:00 AM -1 TJU31
0570006 5/28/2003 12:00:00 AM -1 TJU24
0570010 6/3/2003 12:00:00 AM -1 TJU02
0570010 5/30/2003 12:00:00 AM -1 TJU24
0570017 6/3/2003 12:00:00 AM -1 TJU24
0570018 5/29/2003 12:00:00 AM -4 TJU02
0570018 5/31/2003 12:00:00 AM -3 TJU02
0570018 5/28/2003 12:00:00 AM -2 TJU02
0570018 5/30/2003 12:00:00 AM -2 TJU02
0570018 6/3/2003 12:00:00 AM -2 TJU02
0570018 6/2/2003 12:00:00 AM -2 TJU02
0570018 6/1/2003 12:00:00 AM -1 TJU02
0570018 5/30/2003 12:00:00 AM -6 TJU24
0570018 6/1/2003 12:00:00 AM -6 TJU24
0570018 6/2/2003 12:00:00 AM -5 TJU24
0570018 6/3/2003 12:00:00 AM -3 TJU24
0570018 5/31/2003 12:00:00 AM -2 TJU24
0570018 5/28/2003 12:00:00 AM -1 TJU24
0570018 6/9/2003 12:00:00 AM -4 TJU31
0570019 6/2/2003 12:00:00 AM -3 TJU24
0570019 5/28/2003 12:00:00 AM -1 TJU24
0570019 6/9/2003 12:00:00 AM -1 TJU31
0570020 6/3/2003 12:00:00 AM -2 TJU02
0570020 5/31/2003 12:00:00 AM -1 TJU02
0570020 6/2/2003 12:00:00 AM -1 TJU02
0570020 6/1/2003 12:00:00 AM -1 TJU24
And this should be the result
Item trans_date sum( Quantity ) Location
========================================
0570004 5/29/2003 12:00:00 AM -1 TJU02
0570004 6/3/2003 12:00:00 AM -1 TJU24
0570004 6/9/2003 12:00:00 AM -1 TJU31
0570006 5/28/2003 12:00:00 AM -1 TJU24
0570010 6/3/2003 12:00:00 AM -1 TJU02
0570010 5/30/2003 12:00:00 AM -1 TJU24
0570017 6/3/2003 12:00:00 AM -1 TJU24
0570018 5/29/2003 12:00:00 AM -16 TJU02
0570018 5/30/2003 12:00:00 AM (or 6/1/2003 12:00:00 AM ) -23 TJU24
0570018 6/9/2003 12:00:00 AM -4 TJU31
0570019 6/2/2003 12:00:00 AM -4 TJU24
0570019 6/9/2003 12:00:00 AM -1 TJU31
0570020 6/3/2003 12:00:00 AM -4 TJU02
0570020 6/1/2003 12:00:00 AM -1 TJU24
I have a question I run this query:
SELECT distinct a.ITEM, a.TRANS_DATE,a.LOCATION,
b.tot_QUANTITY
FROM ICTRANS a,
(
SELECT ITEM, LOCATION,SUM(QUANTITY) tot_QUANTITY,
MAX(QUANTITY)
max_QUANTITY
FROM ICTRANS WHERE COMPANY = 2000
-- and LOCATION='TJU02'
AND TRANS_DATE BETWEEN (CURRENT_DATE-14) AND CURRENT_DATE
AND DOC_TYPE = 'IS' AND REASON_CODE = 'VTCL'
AND SUBSTR(ITEM,2,2) = '57'
GROUP BY ITEM ,LOCATION
) b
WHERE a.ITEM='0570018' AND a.ITEM = b.ITEM
AND a.QUANTITY = b.max_QUANTITY
AND a.LOCATION=b.LOCATION
AND a.TRANS_DATE BETWEEN (CURRENT_DATE-14) AND CURRENT_DATE;
Just for 1 item and afther 4:12 minutes I have the results, the table
ICTRANS have 4,628,226 rows, that is normal?
When I tried to run the instruccion with out the item='0570018' it
never
ends.
>>> [EMAIL PROTECTED] 06/10/03 05:29PM >>>
Your query returns the maximum quantity (and associated date) for a
single
ICTRANS entry. If there are multiple entries per day then the logic
is a
lot more complex - but certainly achievable. Since we don't know how
data
is stored in the table though the query below MAY be valid.
"Chelur, Jayadas
{PBSG}" To: Multiple
recipients of list ORACLE-L <[EMAIL PROTECTED]>
<[EMAIL PROTECTED] cc:
epsi.com> Subject: RE: How to
put a
TOP 1 in a select
Sent by:
[EMAIL PROTECTED]
.com
11/06/2003 04:25
Please respond to
ORACLE-L
This query would give you the total quantity sold in the
past two weeks and the date on which maximum number was
sold, for each item ...
SELECT a.item,
a.tras_date AS max_sale_date,
b.tot_qty AS tot_sale_qty
FROM ICTRANS a,
(
SELECT item, SUM(qty) tot_qty, MAX(qty) max_qty
FROM ICTRANS
WHERE company = 2000
AND trans_date BETWEEN TRUNC(SYSDATE-14) AND SYSDATE
AND doc_type = 'IS'
AND reason_code = 'VTCL'
AND SUBSTR(item,2,2) = '57'
GROUP BY item
) b
WHERE a.item = b.item
AND a.qty = b.max_qty
AND trans_date BETWEEN TRUNC(SYSDATE-14) AND SYSDATE;
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