select <columns> from <table> A)
where <predicates>
  and datecreated = (select min(datecreated)
        from <table> b where b.cid = a.cid and b.pid = a.pid)


At 08:14 PM 6/13/2003 -0800, you wrote:
I have a table with records like this


CID S TO_CHAR(DATECREATED, MESSAGE PID
--------- - -------------------- -------------------- ----------
2 N 01-feb-1974 19:45:45 service change 1 *
3 N 01-feb-1974 19:45:45 service change 1 *
3 N 01-feb-1974 21:45:45 service change 1
1 N 01-jan-1974 12:34:45 msisdn change 1 *
1 N 01-jan-1974 19:45:45 service change 1
2 N 01-jan-1974 19:45:45 service change 1
1 N 01-nov-1974 17:45:45 service change 1
1 N 01-nov-1974 19:45:45 service change 1




I want to display only the records with the *(not a value stored in the database.just used as a marker here).
i.e the records which meet the following.


1.earliest date
2.if there are multiple occurances of records with the same cid and pid combination i want only the record for
the combination of cid-pid and with the most earliest record(oldest time stamp).


i want to achieve this


CID S TO_CHAR(DATECREATED, MESSAGE PID
--------- - -------------------- -------------------- ----------
2 N 01-feb-1974 19:45:45 service change 1 *
3 N 01-feb-1974 19:45:45 service change 1 *
1 N 01-jan-1974 12:34:45 msisdn change 1 *


I need some help in getting the query that can get the results like that.

Thanks
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