Metalink note 1011840.102 describes this.

Tanel.
P.S. I spelled algorithm wrong in my last post, now I'm a bit wiser again ;)

----- Original Message ----- 
To: <[EMAIL PROTECTED]>
Sent: Monday, September 08, 2003 6:13 PM


> Tim,
>
> AFAIK, when doing a rebuild the whole index is read using fast full scan,
> the branch blocks are just ignored. And sorting does occur, since fast
full
> scan doesn't guarantee all keys to be returned in an order. (yes the keys
> come in ordered "chunks" because they are stored in ordered way inside
leaf
> blocks, that might help the ordering alghoritm to complete faster).
>
> The benefit comes from that indexes are usually smaller in size than
tables
> because they index only subset of a row, thus there are less IO operations
> needed when scanning data.
>
> Tanel.
>
> ----- Original Message ----- 
> From: "Tim Gorman" <[EMAIL PROTECTED]>
> To: "Multiple recipients of list ORACLE-L" <[EMAIL PROTECTED]>
> Sent: Monday, September 08, 2003 4:49 PM
> Subject: Re: How to speed up index creation
>
>
> Gunnar,
>
> Using ALTER SESSION to increase SORT_AREA_SIZE to some obscene number
(i.e.
> several hundred Mb?  A Gb?) may help, as long as you are running 8i or
below
> or (if running 9i) the parameter WORKAREA_SIZE_POLICY is set to MANUAL.
If
> WORKAREA_SIZE_POLICY is set to AUTO, then you may have to bump
> PGA_AGGREGATE_TARGET to something enormous instead...
>
> Are you making use of ALTER INDEX REBUILD to rebuild an index, or are you
> dropping and then creating?  ALTER INDEX REBUILD runs much faster than a
> CREATE INDEX for two reasons:  1) the REBUILD reads the previous index�s
> leaf nodes so there is less I/O since it is smaller and 2) there is no
sort
> operation needed since the previous index�s leaf entries are already
sorted=
>


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Author: Tanel Poder
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