SELECT DISTINCT testid
, FIRST_VALUE(name) OVER (PARTITION BY testid ORDER BY ROWID) name
, FIRST_VALUE(status) OVER (PARTITION BY testid ORDER BY ROWID) status
FROM testing
/
--
Vladimir Begun
The statements and opinions expressed here are my own and
do not necessarily represent those of Oracle Corporation.elain he wrote:
Hi, Could someone shed some light on this.
I'm trying to formulate a query to return distinct value on a column - testid.
select * from testing; TESTID NAME STATUS ---------- -------------------- ----------- 1 MIKE Y 1 JOE Y 1 JIM Y 2 AMY Y
The output I'm expecting is TESTID NAME STATUS ---------- -------------------- ----------- 1 MIKE Y 2 AMY Y
The query should display the first occurence of the testid and ignore records with the same testid.
-- Please see the official ORACLE-L FAQ: http://www.orafaq.net -- Author: Vladimir Begun INET: [EMAIL PROTECTED]
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