Here are a number of examples using the OWA_PATTERN package:
declare
tstr varchar2(100) := 'this contains tabs multiple spaces and single spaces';
begin
dbms_output.put_line( tstr);
owa_pattern.change( tstr, '\s', '', 'g');
dbms_output.put_line( tstr);
end;
/
declare
tstr varchar2(100) := 'this c34ontains s0239everal 2340 numeric 882 dig2its';
begin
dbms_output.put_line( tstr);
-- remove the digits
owa_pattern.change( tstr, '\d', '', 'g');
dbms_output.put_line( tstr);
-- remove the extra spaces
owa_pattern.change( tstr, '\s+', ' ', 'g');
dbms_output.put_line( tstr);
end;
/
drop table owatest;
create table owatest (
test varchar2(20)
)
/
insert into owatest values('non numeric row');
insert into owatest values('numeric 23423 row');
commit;
select *
from owatest
where owa_pattern.amatch(test,1,'^.*\d') > 0
/
drop table regex;
create table regex (
test varchar2(20)
);
create or replace function strip_str (
data_in varchar2
--, regex_in varchar2
)
return varchar2
is
test_str varchar2(4000);
begin
test_str := data_in;
--owa_pattern.change(test_str, regex_in, '', 'g');
owa_pattern.change(test_str, '\x0a', '', 'g');
owa_pattern.change(test_str, '\x0c', '', 'g');
owa_pattern.change(test_str, '\x0d', '', 'g');
return test_str;
end;
/
show error function strip_str
insert into regex values( 'carriage' || chr(13) || 'return');
insert into regex values( 'line' || chr(10) || 'feeds' || chr(10));
insert into regex values( 'form feed' || chr(12));
commit;
select test
from regex;
select strip_str(test) test
from regex
/
| "Shiva Maran" <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED] 11/06/2003 11:19 PM
|
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]> cc: Subject: pattern search |
Hi All,
I need a means to search for a pattern (With basic wildcard characters like %, _, ^, []). How do I do this in oracle. I also need to get back the string that matches the pattern. Is there any predefined function or procedure that does this. Would like to avoid implementing this on my own.
TIA,
ShivaM
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