Try milliseconds from the epoch - 1/1/1970
select to_date('01/01/1970','mm/dd/yyyy') + ( 1069716948959 / (24*60*60*1000) ) from dual
You really need to know how the timestamp column is defined by your app.
Jared
| "Nguyen, David M" <[EMAIL PROTECTED]>
Sent by: [EMAIL PROTECTED] 12/16/2003 02:09 PM
|
To: Multiple recipients of list ORACLE-L <[EMAIL PROTECTED]> cc: Subject: RE: Unreadable time_stamp format |
Now I got.
USER_NAME TIME STAMP
-------------------- ----------------------
eholley 1069716948959
jmdavis 1069715246467
jmdavis 1069715324466
-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Bobak, Mark
Sent: Tuesday, December 16, 2003 3:54 PM
To: Multiple recipients of list ORACLE-L
Subject: RE: Unreadable time_stamp format
Since it's a NUMBER datatype, try:
SQL> column time_stamp format 99999999999999999999
SQL> select user_name, time_stamp from USER_ACTIVITY_LOG;
-----Original Message-----
From: Nguyen, David M [mailto:[EMAIL PROTECTED]
Sent: Tuesday, December 16, 2003 4:39 PM
To: Multiple recipients of list ORACLE-L
Subject: Unreadable time_stamp format
I need to view time_stamp column in USER_ACTIVITY_LOG table but it displays unreadable format as shown below. Is there a way to decode it to be readable?
SQL> desc USER_ACTIVITY_LOG
Name Null? Type
----------------------------------------- -------- ----------------------------
TIME_STAMP NOT NULL NUMBER(20)
NODE_NAME NOT NULL VARCHAR2(20)
USER_NAME NOT NULL VARCHAR2(20)
CLIENT_IP NOT NULL VARCHAR2(15)
DESCRIPTION NOT NULL VARCHAR2(2048)
SQL>select user_name, time_stamp from USER_ACTIVITY_LOG;
edscott 1.0693E+12
edscott 1.0693E+12
edscott 1.0693E+12
edscott 1.0693E+12
jmdavis 1.0693E+12
edscott 1.0693E+12
edscott 1.0693E+12
Thanks,
David
