I think that
ltrim(to_char(n), '0') || 'A'
gives the same result as
to_char(n) || 'A'
If you want to retain the leading zero but drop any trailing zeros you can
do:
WITH nums AS
(SELECT 0.008499 n FROM dual UNION ALL
SELECT 0.01795 n FROM dual UNION ALL
SELECT 0.05390 n FROM dual UNION ALL
SELECT 0.1078 n FROM dual UNION ALL
SELECT 0.0082 n FROM dual UNION ALL
SELECT 0.01366667 n FROM dual UNION ALL
SELECT 0.00969 n FROM dual
)
SELECT rtrim (to_char(n,'0.999999999'),'0') || 'A' res FROM nums;
2011/3/17 Ivan Doroshenko <zider...@gmail.com>
> Using to_char formatting mask implies fixed result length.
> If you want variable length, try:
>
> WITH nums AS
> (SELECT 0.008499 n FROM dual UNION ALL
> SELECT 0.01795 n FROM dual UNION ALL
> SELECT 0.0539 n FROM dual UNION ALL
> SELECT 0.1078 n FROM dual UNION ALL
> SELECT 0.0082 n FROM dual UNION ALL
> SELECT 0.01366667 n FROM dual UNION ALL
> SELECT 0.00969 n FROM dual
> )
>
> SELECT ltrim(to_char(n), '0') || 'A' res FROM nums
>
>
> On 16 мар, 21:39, teo <teomana...@gmail.com> wrote:
> > Hi everyone,
> >
> > I have a table with NUMBER(38,8) column named PRICE. Below there are
> > some values of this table.
> >
> > 0,008499
> > 0,01795
> > 0,0539
> > 0,1078
> > 0,0082
> > 0,01366667
> > 0,00969
> >
> > I need to concat this values with a text. I use to_char(PRICE) || 'A'
> > the result is like below. Bu as you can see there are no zero (0) How
> > can i concat this values exactly?
> >
> > ,008499A
> > ,01795A
> > ,0539A
> > ,1078A
> > ,0082A
> > ,01366667A
> > ,00969A
>
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