As far as I can tell:
1) this does not belong in the WHERE clause
2) the entire DECODE function could simply be replaced by (date1 > date2)
Consider the following example:
In case you don't know, DUAL is a table that has one column and one row.
The column's name is "dummy" and the value of the row is "X".
SQL> select dummy from dual
DUMMY
-----
X
1 row selected.
SQL> SELECT CASE WHEN dummy = 'X' AND SYSDATE + 1 > SYSDATE
THEN 'A'
WHEN dummy = 'X'
THEN 'B'
ELSE 'R' END result
FROM dual
RESULT
------
A
1 row selected.
SQL> SELECT CASE WHEN dummy = 'X' AND SYSDATE > SYSDATE
THEN 'A'
WHEN dummy = 'X'
THEN 'B'
ELSE 'R' END result
FROM dual
RESULT
------
B
1 row selected.
On Mon, Feb 24, 2014 at 6:59 AM, Sagar Thakkar <saagar.thak...@gmail.com>wrote:
> HI can some explain the case function below specially the DECODE (SIGN
> (TO_DATE (:P_CHK_RECD_TO, 'DD/MM/RRRR') -
> (TO_DATE('10/02/2014','DD/MM/RRRR'))), 1, 'A') = 'A'
>
> WHERE CASE
> WHEN Y.DOC_STATUS = 'R' AND DECODE (SIGN (TO_DATE
> (:P_CHK_RECD_TO, 'DD/MM/RRRR') - (TO_DATE('10/02/2014','DD/MM/RRRR'))), 1,
> 'A') = 'A'
> THEN
> 'A'
> WHEN Y.DOC_STATUS = 'A'
> THEN
> 'A'
> ELSE
> 'R'
> END = 'A'
>
> On Friday, August 12, 2011 3:45:41 AM UTC+3, JK wrote:
>>
>> The decode always returns the date format in DD-MMM-YY format whereas I
>> want it to return in MM/DD/YYYY format.
>>
>> select decode(to_date(to_char(SYSDATE,'YYYYMM'),'YYYYMM'),'
>> 000000',null,to_date(to_char(SYSDATE,'YYYYMM'),'YYYYMM')) from dual.
>>
>> As of now, when I type this I do not have a proper SQL editor to test the
>> syntax. Hence it may not be correct. However, I could run the decode query
>> in TOAD at my work and that is when I saw it is returning in DD-MMM-YY
>> format. I hope you got some idea as to what my requirement is. Looking
>> forward to your help.
>>
>>
>> Thanks in advance.
>>
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