Hi,
You're right, we missed this simple syntax to remove item from Lists:

update #5:12 remove 0 <- there 0 is the position.

Please could you open a new issue for that?

Lvc@




On 24 March 2014 22:33, Jonathan Rosen <[email protected]> wrote:

> let's say i have an embedded set field "people" in record #5:12:
>
> ["bob", "jon"]
>
> this doesnt seem to work:
> update #5:12 remove people[0]
>
> this does work however: update #5:12 remove "bob"
>
> is there any way to remove items by reference, as in case #1?
>
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