Sorry, i deleted the last message after some minutes cause i noticed, that
my database was locked (dont know why)
Its working!
But anyway i think i have another question.
This is the method to create a edge:
edge = this.graph.addEdge(id, outVertex, inVertex, edgeName);
so to create a new edge i need the out and the in vertex. i process my data
in the following way
1. I parse all classes (vertex types)
2. I parse all instances (vertices)
3. I parse all edges (schemaless)
So that means when i create my edges i have to find my in vertex and my out
vertex.
What is the most efficient way to do it? At the moment i do it like that:
public void createEdge(String edgeName, String outID, String outClass,
String inID, String inClass, String property) {
Vertex outVertex = null;
Vertex inVertex = null;
Edge edge = null;
for(Vertex vertex : this.graph.getVerticesOfClass(outClass)) {
if(vertex.getProperty("ID").equals(outID)) {
outVertex = vertex;
}
}
for(Vertex vertex : this.graph.getVerticesOfClass(inClass)) {
if(vertex.getProperty("ID").equals(inID)) {
inVertex = vertex;
}
}
edge = this.graph.addEdge(null, outVertex, inVertex, edgeName);
if(property != null) {
if(DataType.isInteger(property)) {
edge.setProperty("value", Integer.valueOf(property));
} else if(DataType.isDouble(property)) {
edge.setProperty("value", Double.valueOf(property));
} else if(DataType.isBoolean(property)) {
edge.setProperty("value", Boolean.valueOf(property));
} else if(DataType.isDate(property)) {
edge.setProperty("value", Date.valueOf(property));
} else {
edge.setProperty("value", property);
}
}
this.inkrementStatementCounter();
}
In my opinion it is not very efficient to iterate over all vertices of a
given class to find the vertex with
the correct id.
Is there a more efficient way?
Am Mittwoch, 9. April 2014 11:34:10 UTC+2 schrieb Lvc@:
>
> Hi Marc,
> where did you get a timeout? Can you post here the full exception? What
> release are you using?
>
> Lvc@
>
>>
>>
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