Thank you, will test this when I reimport everything and then write here
about the performance.
Am Montag, 8. September 2014 21:19:42 UTC+2 schrieb odbuser:
>
> The only method that returns a single Vertex is noTxGraph.getVertex(Object
> id);
>
> So if you know there's only one vertex (or if you just want the first
> result), just do:
>
> noTxGRaph.getVertices("Person.ID", 1).iterator().next()
>
> I typically hide this behind an api so that I essentially a single Vertex
> return version of getVertices to avoid iterator().next() all over my code.
>
> On Monday, September 8, 2014 7:56:04 AM UTC-4, Curtis Mosters wrote:
>>
>> I have
>>
>> for (Vertex person : noTxGraph.getVertices("Person.ID", 1) {
>> for (Vertex appln : noTxGraph.getVertices("Appln.ID", 1) {
>> noTxGraph.addEdge(null, person, appln, "WROTE");
>> }
>> }
>>
>> What gives back all entries with Appln.ID=1 and same on Person.ID
>>
>> But I know that it's UNIQUE so it does not make any sense. So how can I
>> say
>>
>> noTxGraph.addEdge(null, noTxGraph.getVertex("Person.ID", 1), noTxGraph.
>> getVertex("Appln.ID", 1), "WROTE");
>>
>> That would be much faster in case of Memory usage and transfer. Also much
>> shorter.
>>
>> Is this possible. When yes how. Thank you.
>>
>> Btw: if possible not with an SQLCommand!
>>
>
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