1. I have created issue for countEdges() in OrientVertex
https://github.com/orientechnologies/orientdb/issues/3040
2. Mine is not lightweight edges. Becuase, I have 1 or 2 properties in Edges
3. In the query (select from E where out = ? and in = ? limit 1), how
should I give the argument. is it line startOrientVertex.getId().toString()
and endOrientVertex.getId().toString()?
4. I used the following code to create composite index for out and in...
g.createKeyIndex("key", Edge.class, new Parameter("class", "metoptp"), new
Parameter("type", "unique_hash_index")); //This index is for uniqueKey
System.out.println("e index created");
OrientEdgeType edgeType = g.getEdgeType("metoptp");
OIndex<?> createIndex = edgeType.createIndex("out_in",
OClass.INDEX_TYPE.UNIQUE, "out", "in");
Here, I am getting the below Exception
Exception in thread "main"
com.orientechnologies.orient.core.index.OIndexException: Index with name :
'out_in' cannot be created on class : 'metoptp' because field: 'out' is
absent in class definition.
at
com.orientechnologies.orient.core.metadata.schema.OClassImpl.createIndex(OClassImpl.java:1418)
at
com.orientechnologies.orient.core.metadata.schema.OClassImpl.createIndex(OClassImpl.java:1391)
at
com.orientechnologies.orient.core.metadata.schema.OClassImpl.createIndex(OClassImpl.java:1381)
at
com.orientechnologies.orient.core.metadata.schema.OClassImpl.createIndex(OClassImpl.java:1377)
at
com.orientechnologies.orient.core.metadata.schema.OClassAbstractDelegate.createIndex(OClassAbstractDelegate.java:291)
at
com.tinkerpop.blueprints.impls.orient.OrientElementType.access$301(OrientElementType.java:35)
at
com.tinkerpop.blueprints.impls.orient.OrientElementType$4.call(OrientElementType.java:80)
at
com.tinkerpop.blueprints.impls.orient.OrientElementType$4.call(OrientElementType.java:77)
at
com.tinkerpop.blueprints.impls.orient.OrientBaseGraph.executeOutsideTx(OrientBaseGraph.java:1488)
at
com.tinkerpop.blueprints.impls.orient.OrientElementType.createIndex(OrientElementType.java:77)
at adi.orientdb.eval.OTester.setFactory(OTester.java:142)
at adi.orientdb.eval.OTester.write(OTester.java:157)
at adi.orientdb.eval.OTester.main(OTester.java:44)
On Thursday, November 6, 2014 7:38:46 PM UTC+5:30, Lvc@ wrote:
>
> Hi Adithyan,
> The idea of supporting a countEdges() in OrientVertex is good. Could you
> create a new issue for that?
>
> Do you have lightweight edges between vertices or regular ones? Are
> regulars if they have at least one property. If yes you could
> do:
>
> select from E where out = ? and in = ? limit 1
>
> This would be fast if you create a composite index on E (or the Edge class
> you're using) and fields out + in.
>
> Lvc@
>
>
> On 6 November 2014 12:20, Adithyan K <[email protected] <javascript:>>
> wrote:
>
>> I am using OrientDB-2.0-M2 version.
>>
>> My objective is to identify whether a edge with particular label exists
>> between a start vertex and end vertex. I am using the following method for
>> that
>>
>> private boolean existsRelationship(Relationship relationship) throws
>> Exception
>> {
>> OrientVertex start = getVertex(relationship.getStartNodeUniqueKey());
>> OrientVertex end = getVertex(relationship.getEndNodeUniqueKey());
>> Iterator<Edge> iter = start.getEdges(end,
>> com.tinkerpop.blueprints.Direction.OUT, relationship.getType()).iterator();
>> return *iter.hasNext();*
>> }
>> I don't know whether this approach is the efficient way to find edge
>> existence.
>>
>> In this approach, more than 60% of the CPUs time is spend in
>> iter.hasNext() method. I am attaching the screenshot here. Pls check.
>> Comparing the load of millions of nodes/edges addition, I feel
>> iter.hasNext() is tooooo expensive.
>>
>> My objective is to find only the existence. For that, getting edges may
>> not be so efficient, i feel. I am not finding OrientVertex.countEdges()
>> method that accepts destination OrientVertex.
>>
>> *My Points*
>>
>> 1. Is there any other better way of checking the existence of a edge
>> given its startnode, end node and label???
>> 2. You can check in the attached screenshot (taken using JMC version 5.4)
>> whether this iter.hasNext() can be so expensive?
>> 3. If possible, you can give some lazily loadable object in such a way
>> that hasNext() just checks the size and current Pointer to return true or
>> false
>> 4. Is it possible to have OrientVertex.countEdges(OrientVertex
>> destination, Direction direction, String... labels)
>>
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>>
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>
>
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