Hi Keith.
I don't like very much your example, since I'm expecting that edges with
different labels could exists between the same two vertices.
>From the last documentation I thought that the first edge created was
lightweight and the following were created as record.
Anyway I used your code to produce another example, which I think is more
appropriated:
import com.tinkerpop.blueprints.Direction;
import com.tinkerpop.blueprints.Edge;
import com.tinkerpop.blueprints.impls.orient.OrientEdge;
import com.tinkerpop.blueprints.impls.orient.OrientGraphFactory;
import com.tinkerpop.blueprints.impls.orient.OrientGraphNoTx;
import com.tinkerpop.blueprints.impls.orient.OrientVertex;
public class O2GraphLWEdges
{
public static void main(String[] args)
{
long start = System.currentTimeMillis();
OrientGraphFactory gfactory = new OrientGraphFactory("memory:temp");
try
{
OrientGraphNoTx graph = gfactory.getNoTx(); // get an instance
from the pool
graph.setUseLightweightEdges(true);
try
{
OrientVertex v1 = graph.addVertex("class:V1", "name",
"Luca");
OrientVertex v2 = graph.addVertex("class:V1", "name",
"Marko");
OrientEdge e = graph.addEdge(null, v1, v2, "knows");
if(e.isLightweight())
System.out.println("created lightweight edge");
e = graph.addEdge(null, v1, v2, "knows");
if(e.isLightweight())
System.out.println("created lightweight edge");
e = graph.addEdge(null, v1, v2, "knows");
if(e.isLightweight())
System.out.println("created lightweight edge");
e = graph.addEdge(null, v1, v2, "knows");
if(e.isLightweight())
System.out.println("created lightweight edge");
System.out.println("Edges as Record: " +
Long.toString(graph.countVertices("E")));
Iterable<Edge> edges = v1.getEdges(Direction.OUT);
long i = 0;
for(Edge edge : edges)
i += 1;
System.out.println("Outgoung Edges startign from v1: " +
Long.toString(i));
}
catch (Exception ex)
{
try
{
graph.rollback();
}
catch (Exception ex1)
{
System.err.println("rollback exception! " + ex);
}
System.err.println("operation exception! " + ex);
ex.printStackTrace(System.err);
}
finally
{
graph.shutdown();
}
}
catch (Exception ex)
{
System.err.println("instance exception! " + ex);
ex.printStackTrace(System.err);
}
finally
{
gfactory.close();
}
System.out.println("done in " + (System.currentTimeMillis() -
start) + "ms");
}
}
The output is (Orient 1.7.10):
created lightweight edge
created lightweight edge
created lightweight edge
created lightweight edge
Edges as Record: 0
Outgoung Edges startign from v1: 4
done in 787ms
*My expectations where all wrong: multiple lightweight edges, with the same
label, between the same vertices can exist.*
I can't clearly state if it's a bug or it's a feature, but documentation
should be fixed.
Cheers,
Riccardo
Il giorno mercoledì 7 gennaio 2015 20:55:10 UTC+1, Keith Freeman ha scritto:
>
> Sorry, but I don't think the correction is right either: "two vertices are
> connected by maximum 1 edge, so if you already have one edge between two
> vertices and you're creating a new edge between the same vertices, the
> second edge will be regular."
>
> I just wrote a quick java program (on 2.0-rc1) that creates 2 vertices and
> 4 edges between them, all 4 edges are lightweight. It seems the only real
> condition is that the edge have no properties (and of course that the
> database is configured for lightweight edges).
>
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