Can someone tell me what the unaccounted for bytes are before the Binary
Schemaless Serialization result below? (The unaccounted for short, byte,
short, long, int) The protocol command used was an idempotent
REQUEST_COMMAND.
Thanks,
Philip Wernersbach
2015-02-07 16:50:24:651 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Read 39 bytes: qselect from sung_by*:1 [OChannelBinaryServer]
2015-02-07 16:50:24:666 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing byte (1 byte): 0 [OChannelBinaryServer]
2015-02-07 16:50:24:667 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing int (4 bytes): 2 [OChannelBinaryServer]
2015-02-07 16:50:24:670 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing byte (1 byte): 108 [OChannelBinaryServer] => synch-result-type
2015-02-07 16:50:24:670 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing int (4 bytes): 2 [OChannelBinaryServer] => # of records returned
2015-02-07 16:50:24:714 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing short (2 bytes): 0 [OChannelBinaryServer] => ???
2015-02-07 16:50:24:718 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing byte (1 byte): 100 [OChannelBinaryServer] => ???
2015-02-07 16:50:24:718 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing short (2 bytes): 13 [OChannelBinaryServer] => ???
2015-02-07 16:50:24:719 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing long (8 bytes): 0 [OChannelBinaryServer] => ???
2015-02-07 16:50:24:719 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing int (4 bytes): 3 [OChannelBinaryServer] => ???
2015-02-07 16:50:24:721 INFO {db=GratefulDeadConcerts} /127.0.0.1:50985 -
Writing bytes (4+31=35 bytes): [0, 14, 115, 117, 110, 103, 95, 98, 121, 6,
111, 117, 116, 0, 0, 0, 27, 13, 4, 105, 110, 0, 0, 0, 29, 13, 0, 18, 2, 18,
16] [OChannelBinaryServer] => Binary Schemaless Serialization
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