ah, I suggest you to define an index (NOTUNIQUE) on the score property, this query will become extremely fast
Luigi 2015-06-12 18:43 GMT+02:00 Luigi Dell'Aquila <[email protected]>: > Hi Marteen, > > the easiest thing you can do is this: > > select outV().name as personName, inV().name as taskName, score from > Performs order by score DESC > > Luigi > > > 2015-06-12 18:16 GMT+02:00 Maarten Berkenbosch <[email protected]>: > >> How do I join person.name, performs.score, task.name into one query >> result that displays the top 10 scores? >> Or should I assemble the list with multiple queries? >> >> (Vertex) Person.name >> (Edge) Performs.score >> (Vertex) Task.name >> >> -- >> >> --- >> You received this message because you are subscribed to the Google Groups >> "OrientDB" group. >> To unsubscribe from this group and stop receiving emails from it, send an >> email to [email protected]. >> For more options, visit https://groups.google.com/d/optout. >> > > -- --- You received this message because you are subscribed to the Google Groups "OrientDB" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. For more options, visit https://groups.google.com/d/optout.
