Hi,
  have you tried: $unique = $conv.asSet() ?

Cheers,
   Riccardo

2015-07-14 20:24 GMT+02:00 Ran Mizrachi <[email protected]>:

> Hi All,
>
> I'm trying to get distinct set in a query results but can't make it work.
> I would appreciate your assistance.
>
> My query:
>
> select uid, name, $conv,  $unique
> from (select expand(outE("HasCard").inV()) from #12:1310)
> let
> $conv = inV().inE().outV("Conversation"),  // I'm getting list of @rid ->
> [#13:23, #13:23, #13:55]
> $unique = distinct($conv)  // trying to get [#13:23, #13:55]
>
> I also tried to change the last line to:
> $unique = (select @rid from Conversation where @rid in $conv)
> but it didn't work too.
>
> Thank you very much for helping!
>
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