Thanks for the reply. I never noticed it until now, when I am trying to do
something similar again.
I understand what you are saying, but I can't fathom the syntax. Can you
give an example?
On Thursday, 14 May 2015 12:31:47 UTC+8, Ziink A wrote:
>
> I know this is a very late response but it's mostly for someone who's
> looking as I was.
>
> ContainsAll implies that the collection on the left 'contains all' the
> items on the right.
>
> THAT IS NOT SO.
>
> On the right of CONTAINSALL should be a condition. All elements in the set
> on the left must satisfy the condition on the right.
>
>
>
> On Wednesday, March 11, 2015 at 12:45:59 AM UTC-7, neRok wrote:
>>
>> I am attempting to do a query to find all of a particular vertex that
>> have the same incoming edges to other vertexes . Using the following works
>> (and probably explains it better)...
>> SELECT FROM Person WHERE in('Child') contains #12:1 and in('Child')
>> contains #12:6
>> But none of the following do (they return 0 records)...
>> SELECT FROM Person WHERE in('Child') CONTAINSALL #12:1,#12:6
>> SELECT FROM Person WHERE in('Child') CONTAINSALL (#12:1,#12:6)
>> SELECT FROM Person WHERE in('Child') CONTAINSALL [#12:1,#12:6]
>> I even tried the above with quotations around the rids. I also tried the
>> following...
>> SELECT FROM Person WHERE in('Child') CONTAINSALL #12:1
>> This returned every Person, the same as if I had of done
>> SELECT FROM Person
>> Am I doing something wrong, or is this not working?
>>
>
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