Hello,
*I am create javascript function using studio.var result = q.command(
"sql",mySQLCommand);*
here result is below json:
[
{
"@type": "d",
"@rid": "#-2:1",
"@version": 0,
"vKRId": "#23:0",
"uRId": "#21:0",
"@fieldTypes": "vKRId=x,uRId=x"
}
]
I want read vKRId and uRId values from result variable. I tried using
JSON.parse or JSON.stringfy, it gives below error
SyntaxError: Invalid JSON: <json>:1:0 Expected json literal but found
What is best practice to parse query result?
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