Gin,
Each pixel of your image is handled as a n-dimensional row vector, with n
the number of bands in your image. {n1, n2, n3, ...} is the syntax of
muParserX to declare row vectors that you can fill with scalars assigned by
band.
Hope it helps.
Arnaud
Le jeudi 23 avril 2015 14:10:28 UTC+2, GiNN a écrit :
>
> Thank Arnaud,
>
> And yes, d and e are scalars. In fact, they are constant for the entire
> image, while the image has three bands.
>
> If I understand you correctly, this still counts as a vector
> transformation?
> On Apr 23, 2015 7:50 AM, "Arnaud Durand" <[email protected]
> <javascript:>> wrote:
>
>> Hi GiNN,
>>
>> I'm not sure that it is possible with such a simple expression, as the
>> doc said :
>>
>>
>>
>> *For instance, it is not possible to add vectors of different dimensions
>> (this implies the addition of a row vector with a column vector),or add a
>> scalar to a vector or a matrix, or divide two vectors, and so on...Thus, it
>> is important to remember that a pixel of n components is always represented
>> as a row vector.*
>>
>> However, if you know the number of bands in your image, and if d and e
>> are scalars, you might try to use vector syntax in your expression like
>> that : im1*{d^2,d^2,d^2,d^2}/{cos e, cos e, cos e, cos e}
>>
>> Arnaud
>>
>> Le mercredi 22 avril 2015 21:02:15 UTC+2, GiNN a écrit :
>>>
>>>
>>> I have three-band images and I want to apply the same expression to each
>>> band and get a three-bad output.
>>> I am just starting with OTB and Monteverdi. Used installer on a 64 bit
>>> W7 machine.
>>>
>>> The expression is very simple: output_pixel = (input_pixel*d^2)/cos e
>>>
>>> I read the cookbook recipe, and concluded BandmahX is what I need. But I
>>> am not sure how to formulate the expression so that the application goes
>>> through all pixels in all three bands.
>>>
>>> Any assistance is greatly appreciated.
>>>
>>> Gin
>>>
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