On 26/06/2018 13:28, Eelco Chaudron wrote:
> 
> 
> On 22 Jun 2018, at 21:04, Lam, Tiago wrote:
> 
>> On 18/06/2018 12:55, Eelco Chaudron wrote:
>>>
>>>
>>> On 11 Jun 2018, at 18:21, Tiago Lam wrote:
>>>
>>>> In its current implementation dp_packet_shift() is also unaware of
>>>> multi-seg mbufs (that holds data in memory non-contiguously) and
>>>> assumes
>>>> that data exists contiguously in memory, memmove'ing data to perform
>>>> the
>>>> shift.
>>>>
>>>> To add support for multi-seg mbuds a new set of functions was
>>>> introduced, dp_packet_mbuf_shift() and dp_packet_mbuf_write(). These
>>>> functions are used by dp_packet_shift(), when handling multi-seg
>>>> mbufs,
>>>> to shift and write data within a chain of mbufs.
>>>>
>>>> Signed-off-by: Tiago Lam <tiago....@intel.com>
>>>> ---
>>>>  lib/dp-packet.c | 102
>>>> ++++++++++++++++++++++++++++++++++++++++++++++++++++++++
>>>>  lib/dp-packet.h |   8 +++++
>>>>  2 files changed, 110 insertions(+)
>>>>
>>>> diff --git a/lib/dp-packet.c b/lib/dp-packet.c
>>>> index 9f8503e..399fadb 100644
>>>> --- a/lib/dp-packet.c
>>>> +++ b/lib/dp-packet.c
>>>> @@ -294,6 +294,102 @@ dp_packet_prealloc_headroom(struct dp_packet 
>>>> *b,
>>>> size_t size)
>>>>      }
>>>>  }
>>>>
>>>> +#ifdef DPDK_NETDEV
>>>> +/* Write len data bytes in a mbuf at specified offset.
>>>> + *
>>>> + * 'mbuf', pointer to the destination mbuf where 'ofs' is, and the
>>>> mbuf where
>>>> + * the data will first be written.
>>>> + * 'ofs', the offset within the provided 'mbuf' where 'data' is to 
>>>> be
>>>> written.
>>>> + * 'len', the size of the to be written 'data'.
>>>> + * 'data', pointer to the to be written bytes.
>>>> + *
>>>> + * XXX: This function is the counterpart of the 
>>>> `rte_pktmbuf_read()`
>>>> function
>>>> + * available with DPDK, in the rte_mbuf.h */
>>>> +void
>>>> +dp_packet_mbuf_write(struct rte_mbuf *mbuf, int16_t ofs, uint32_t
>>>> len,
>>>> +                     const void *data)
>>>> +{
>>>> +    char *dst_addr;
>>>> +    uint16_t data_len;
>>>> +    int len_copy;
>>>> +    while (mbuf) {
>>>> +        if (len == 0) {
>>>> +            break;
>>>> +        }
>>>> +
>>>> +        dst_addr = rte_pktmbuf_mtod_offset(mbuf, char *, ofs);
>>>> +        data_len = MBUF_BUF_END(mbuf->buf_addr, mbuf->buf_len) -
>>>> dst_addr;
>>>> +
>>>> +        len_copy = MIN(len, data_len);
>>>> +        /* We don't know if 'data' is the result of a
>>>> rte_pktmbuf_read() call,
>>>> +         * in which case we may end up writing to the same region 
>>>> of
>>>> memory we
>>>> +         * are reading from and overlapping. Hence the use of
>>>> memmove() here */
>>>> +        memmove(dst_addr, data, len_copy);
>>>> +
>>>> +        data = ((char *) data) + len_copy;
>>>> +        len -= len_copy;
>>>> +        ofs = 0;
>>>> +
>>>> +        mbuf = mbuf->next;
>>>> +    }
>>>> +}
>>>> +
>>>> +static void
>>>> +dp_packet_mbuf_shift_(struct rte_mbuf *dbuf, int16_t dst_ofs,
>>>> +                      const struct rte_mbuf *sbuf, uint16_t 
>>>> src_ofs,
>>>> int len)
>>>> +{
>>>> +    char rd[len];
>>>> +    const char *wd = rte_pktmbuf_read(sbuf, src_ofs, len, rd);
>>>> +
>>>> +    ovs_assert(wd);
>>>> +
>>>
>>> This implementation copies the entire packet to a temp buffer and 
>>> then
>>> copies it back. Would it be "faster" to do a direct memmove, starting
>>> with the last/first segment depending on the direction?
>>>
>>
>> If I understand the question correctly, that would assume that memory 
>> is
>> contiguous in memory, which isn't guaranteed with multi-segment mbufs.
>> Hence why we read to a temp buffer and write all at once (when 
>> writing,
>> in dp_packet_prealloc_tailroom(), we do use memmove() within the same
>> mbuf, where memory is contiguous).
> 
> Assuming the sbuf is continues, no memory is copied to rd, however if 
> it’s not it’s copied, and we move memory twice.
> I’m suggesting to optimise for this case, skip the extra copy, but not 
> sure if this is worth the effort.
> 

OK, I understand your point now. rte_pktmbuf_read() does that internally
- if the data to copy is within the same mbuf (`sbuf` in this case), the
pointer returned by the function is to the data section in the `sbuf`
itself. Only otherwise it copies to `rd` and returns a pointer to `rd`.

Tiago.
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