On Sat, Aug 6, 2011 at 11:43 AM, Taral <[email protected]> wrote: > Sure, if F is X->Y where Y >= 2^X. Otherwise, I don't think so.
This, again, assuming that trivial solutions like F(X...) = 0, G(X,Y) = 0 aren't what you're looking for. Your problem is really woefully underspecified. -- Taral <[email protected]> "Please let me know if there's any further trouble I can give you." -- Unknown _______________________________________________ p2p-hackers mailing list [email protected] http://lists.zooko.com/mailman/listinfo/p2p-hackers
