Should have mentioned i am using windows..
I know how to copy files to the guest vm, i am trying to initiate the copy
from the local windows server i am running packer on. I am doing this
manually using the shell-local command
"type": "Shell-Local"
"command": "xcopy -source C:\packer\vmtools -destination \\guestip\c$\packer
The guest IP i am entering manually by checking which dhcp address is
allocated to the guest IP from my AD server
Packer knows this address already as it connected over SSH/Winrm without me
providing it.. i want to know how i can get it.. using something like
{{guest_IP}}
James
On Friday, 23 June 2017 05:12:14 UTC+10, Rickard von Essen wrote:
>
> You can do something like this:
>
> "provisioners": [
> {
> "type": "shell",
> "inline": [ "hostname > /tmp/hostname" ]
> },
> {
> "type": "file",
> "direction": "download",
> "source": "/tmp/hostname",
> "destination": "hostname"
> }
> ]
>
> And you will get the hostname in the file "hostname".
>
> You just need to switch to ifconfig etc. If you are building in a cloud it
> might also be possible to use the cli/api if you have an unique name/id/tag
> etc to lookup.
>
>
> On Jun 22, 2017 17:27, "James Elmes" <[email protected] <javascript:>>
> wrote:
>
> Howdy.
>
> Wondering if there is a way to return the guest IP. I want to initiate a
> file copy from Shell-Local provisioner, this way the copy is initiated from
> the local machine running packer.
>
> example: xcopy -source C:\packer\vmtools -destination \\guestip\c$\packer
>
> i have looked everywhere and can't seem to find a way to return the actual
> guest IP
>
> any help appreciated
>
> James
>
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