On 16/01/14 02:03, Martti Kühne wrote: > On Wed, Jan 15, 2014 at 9:50 AM, Allan McRae <[email protected]> wrote: > [...] >> >>> + # hash function (x*2+1) is completely arbitrary. >>> + my $repohash = $v[0]; >>> + $repohash =~ s/(.)/ord($1)*2+1/ge; >> >> I have very little perl knowledge, so I have no idea what that hash is >> doing. Can someone explain to me so I can see if that "hash" is reasonable. >> > > Replace each character with its [0] ascii index times two plus one? > 'g' is group regexes, 'e' is eval expressions [1], as to utilize the > result of the calculation. > > cheers! > mar77i > > [0] http://perldoc.perl.org/functions/ord.html > [1] > http://stackoverflow.com/questions/6082219/perl-regex-e-eval-modifier-with-s >
Does that mean the answer can only be odd? Allan
