I remember from years ago using the following algorithm to calculate square
roots on calculators that lacked it.
Problem: Compute the square root of three.
Start with estimate. e.g. 2
(3 / 2 + 2) / 2 = 1.75
(3 / 1.75 + 1.75) / 2 = 1.732
(3 / 1.732 + 1.732) / 2 = .... continue until accurate to the
degree desired.
It seems to converge to the correct answer quickly. I think it is called
Newton's approximation or convergence.
Marty
At 02:24 PM 4/11/99 PDT, you wrote:
>Is there a palm c function that returns the square root of a float?
>If not, does anyone have an algorithm that would work. I want to
>avoid using mathlib because I do not want the user to have to have the
>mathlib.prc . Please feel free to email me directly at
>[EMAIL PROTECTED]
>Thanks in advance,
>Avi I. Smith
>
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