Re: 64 bit integer using 32 bit data types - how

[Michael S. Davis]

On Wed, 25 Aug 1999, Michael S. Davis wrote:

> On Wed, 25 Aug 1999, Kenichi Okuyama wrote:
> 
> > CodeWarrior, have flags to supports long long ( or was it longlong?
> > ) keyword, which stands for 64bit fixed point variable. GCC, as
> > default, also supports keyword "long long" for 64bit fixed point
> > variable.

I must be missing something here.  I tried long long declaration of a
variable and tried to assign a value to it and got a compiler warning.

I created a simple routine to take a hard coded 'long long' and return
the Hex value.  The compiler (GCC) warned that the: 
"the constant value is so large that it is unsigned".  The value input
was representable as a 32 bit integer.  So, it was not too large for 64
bits???

Here is the code:

void DispHex() {
    long long x;
    char hex[17];
    int i;

    x = 2348719048;
    for(i=0;i<16;i++) {
        hex[i] = GetNib(x, i);  // where this returns single char
    }
    hex[16] = 0;
    SetFieldText(fldOutput, hex);  // my routine to display string in
                     field
}

Why does assigning x to this value result in an integer that has a
value that is out of range?  It also displays the wrong value.  What
is the format of the long long?  Is it just a 64 bit binary?

Thanks

Mike (looking for GCC compiler manual) Davis