Thanks, I'll try it w/ "Byte *" ...
--
-Richard M. Hartman
[EMAIL PROTECTED]
186,000 mi./sec ... not just a good idea, it's the LAW!
> -----Original Message-----
> From: Greg Pasquariello [mailto:[EMAIL PROTECTED]]
> Sent: Friday, November 19, 1999 5:44 PM
> To: [EMAIL PROTECTED]
> Subject: RE: Pointer Arithmetic in CW5
>
>
> Pointer arithmetic requires a type. The number that you add
> to the pointer
> is multiplied by the size of the type. So:
>
> char *ptr + 5 is the address of ptr + 5 bytes;
> int *ptr + 5 is the address of ptr + 5 * 4 bytes (assuming
> 4byte integers)
>
> Void * essentially declares that you don't know the type.
>
>
> > -----Original Message-----
> > From: Richard Hartman [mailto:[EMAIL PROTECTED]]
> > Sent: Friday, November 19, 1999 6:33 PM
> > To: '[EMAIL PROTECTED]'
> > Subject: Pointer Arithmetic in CW5
> >
> >
> >
> > I'm having a problem w/ what should be simple
> > pointer arithmetic ... the compiler just won't
> > let me do it! I've pared down the problem, doing
> > things step by step until I get the error on one
> > operation (the math). It's giving me an "Error :
> > illegal type" on the line marked with ">>>"
> >
> > void *p = pDbRec; // cast rec ptr to void ptr to
> > simplify things
> > UInt o = pDbRec->hdr.bDataOffset; // put offset
> into single
> > variable
> > // to simplify
> > things
> > >>> void *p2 = p + o; // add offset to ptr, kablooie!
> >
> >
> > Maybe it's just too late in the day ... but what
> > am I doing wrong?
> >
> > --
> > -Richard M. Hartman
> > [EMAIL PROTECTED]
> >
> > 186,000 mi./sec ... not just a good idea, it's the LAW!
> >
> >
> >
>
>
