> I understand how you can define a ROTL as
>
> #define ROTL(x,y) (((x)<<(y&(w-1))) | ((x)>>(w-(y&(w-1)))))
>
> where w is the number of bits in x and y. But why does this only work
> with unsigned numbers and not signed?
this one i can answer! :P
a shift right ">>" works the way you intend if the number is
unsigned.. however, if you have a negative number, the shifting
works slightly different.
-32 >> 1 should give you -16 right? and what does this tell
you just by looking at it? *the* SIGN bit is maintained, and
hence the MSB is not removed :>
> More importantly, isn't there a built-in hardware instruction to
> do this in the Motorola 68K chips? and how do we put in-line
> assembly into our Palm programs?
asm ("rol.b d0");
or something like that :>
az.
--
Aaron Ardiri
Java Certified Programmer http://www.hig.se/~ardiri/
University-College i G�vle mailto:[EMAIL PROTECTED]
SE 801 76 G�vle SWEDEN
Tel: +46 26 64 87 38 Fax: +46 26 64 87 88
Mob: +46 70 656 1143 A/H: +46 8 668 78 72
if you enjoy it, then it aint work :) - rule #106 of life
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