You need to provide a real chunk of memory big enough to hold the formatted
result in strP, *not* a null ptr.
So
strP = MemPtrNew(3); // or char[3] str, and then use &str in the call
below
StrPrintF(strP, "%02x", hexval);
john Schettino
Palm OS Programming for Dummies, http://schettino.tripod.com
-----Original Message-----
From: Wang, Nancy [mailto:[EMAIL PROTECTED]]
Sent: Wednesday, April 05, 2000 4:32 PM
To: Palm Developer Forum
Subject: StrPrintF
Hello,
I remember some previous posting about StrPrintF crashes. I met the same
problem with the following code:
CharPtr strP = NULL;
Int16 hexval = 128;
StrPrintF(strP, "%02x", hexval);
Does someone know why it crashed? Thanks.
Nancy
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