It won't work. I'm assuming you've declared z as a long int and that you
want to allocate the number of digits in a character buffer. Well,
sizeof(z) will most likely return 4 bytes (depending on your platform) which
isn't enough to hold your numeric string.
I've done something similar and wrote it up in the DDJ January 2000 issue.
Drop by my website for the source code (for CodeWarrior). Look under
EuroCalculator.
--
Michael Yam
www.ytechnology.com
[EMAIL PROTECTED]
Tim Astle <[EMAIL PROTECTED]> wrote in message
news:9437@palm-dev-forum...
>
> How would I correctly allocate the exact amount of memory I require for a
> string, based on an integer result?
>
> For example:
>
> char *s;
> long int x = 12312451, y = 324324;
> z = x + y;
>
> Now I need to place this result into a character array. Would I do this?
> s = (char *)MemPtrNew(sizeof(z));
>
> I'm sure that isn't the correct way to do it, but I need to have the
> information as exact as possible. I later use the information to
determine
> the placement of a decimal in the array.
>
> --
>
> Tim Astle
>
>
>
>
--
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