Say for the following code snippet,
{
void* P;
MemHandle H;H = MemHandleNew(1); P = MemHandleLock(H); MemHandleUnlock(H); } Now, if I substituted MemHandleUnlock(H) for MemPtrUnlock(P), would the lock count for H be reduced to 0? Is there a way to check the lock count of a handle? Ditto for a pointer created with MemPtrNew(). -- For information on using the ACCESS Developer Forums, or to unsubscribe, please see http://www.access-company.com/developers/forums/
