Wow! Thanks! Ed
----- Original Message -----
From: "Tom McCormick" <[EMAIL PROTECTED]>
To: "Palm Developer Forum" <[EMAIL PROTECTED]>
Sent: Wednesday, September 20, 2000 4:24 PM
Subject: RE: strings and string lists
> So, has anyone figured out how much code space is required
> for the resource
> approach as opposed to the hard coded method?
>
>
> (NOTE: All values are numbers of bytes)
>
> For storage space:
>
> Assuming a string with a length of nChars,
>
> a hard-coded string takes nChars + 1 (null terminator) in the dynamic heap
> and
>
> a 'tSTR' resource string takes nChars + 1 (null terminator) plus one chunk
> header for the chunk that the resource (8) is stored in plus one entry in
> the program's DatabaseHeaderType (4). Essentially, nChars + 13 in the
> storage heap.
>
>
>
> For code:
>
> A hard coded string is referred to directly with a pointer (4 in the
dynamic
> heap).
>
> The code for loading the string (this will change given error trapping and
> other techniques for using the string)
>
> VoidHand hString = NULL;
>
> // Get resource
> hString = DmGet1Resource('tSTR', 1000);
>
> // Do sumptin'
> //blah, blah, blah
>
> // Release resource
> DmReleaseResource(hString);
>
> is 36 bytes (by my count) in the storage heap using Code Warrior to
> dissassemble the above code + 8 bytes in the dynamic heap for hString and
> pString.
>
> So, to summarize:
>
> Hard code: (nChars + 1) (storage in dynamic heap) + 4 (code in storage
> heap)
> Resource: (nChars + 13) (storage in storage heap) + 36 (code in storage
> heap) + 8 (code in dynamic heap).
>
> Don't forget (as pointed out before in this thread) the dynamic memory is
> scarcer than storage memory. (The resource technique uses less dynamic
> memory.)
>
>
> Thomas McCormick
> Centennial Technologies
> 7 Lopez Road
> Wilmington, MA 01887
> Phone: (978) 805-2147
> e-mail: [EMAIL PROTECTED]
>
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