Nope, the document states that, though not in the exact words "IT DOES
NOT MAKE A COPY".
->LstSetListChoices (ListType *listP, Char **itemsText, UInt16 numItems)
->Parameters : itemsText Pointer to an array of text strings.
So, u would have to do something like this:
void foo()
{ Char* *strArray;
Char* strBuf;
ListType *lstP;
Int8 i;
/*lstP = ? get the pointer to your list here */
strArray = MemPtrNew(sizeof(Char*));
for (i = 0; i < 10; i++)
{
strBuf = MemPtrNew(5);
StrPrintF(strBuf, "str%d", i);
strArray[i] = strBuf;
}
LstSetListChoices(lstP, strArray, 10);
}
of course, you would have to check the return val of MemPtrNew, I didn't
do it here. Hope this helps!
Jason Garrett wrote:
>
> Does LstSetListChoices() make its own copy for the list to use, or does it continue
>to use the memory that you have indicated in this call?
> Could I destroy my string list, and the list remain happy?
>
> Jason Garrett
> wirelessdata
> Ph: +64 9 379 3710 Fax: +64 9 379 7360 Cell: +64 21 400 307 ICQ: 44334435
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