> This is what I was talking about.... A better approach would be to use
> proper library transforms instead of type-casting...
Is what you are talking about is that the last few values in your printout
should be "4" instead of "-48"? Perhaps if you took the bugs out of your
program, it would work better. "S[10] = '4';" is incorrect. It's assigning '4'
to the 11th element of a 10 element array. Try assigning it to S[0].
-- Keith Rollin
-- Palm OS Emulator engineer
Igor Mozolevsky <[EMAIL PROTECTED]> on 01/30/2001 05:57:05 PM
Please respond to "Palm Developer Forum" <[EMAIL PROTECTED]>
Sent by: Igor Mozolevsky <[EMAIL PROTECTED]>
To: "Palm Developer Forum" <[EMAIL PROTECTED]>
cc: (Keith Rollin/US/PALM)
Subject: Re: GCC Compiler Bug? (Or am I just losing my mind?)
At 17:11 30/01/2001 -0800, you wrote:
>Instead, this integral value of 4 is cast via (double) into a double
>value. The
>string "s" is not converted! Just the result of the expression (s[0] - '0').
>
>-- Keith Rollin
>-- Palm OS Emulator engineer
Incidentally,
#include <stdio.h>
char S[10];
char SS[10];
char SSS[10];
int main(void)
{
S[10] = '4';
memset(SSS, 0, 10);
memset(SS, 0, 10);
(unsigned int) (SS[0]) = (S[0]-'0');
memcpy((void*)SSS, (void*)SS, sizeof(S[0]-'0'));
printf("sizeof(double):%d\nsizeof((S[0]-'0')):%d\nsizeof(char):%d\n",sizeof(double),sizeof((S[0]-'0')),sizeof(char));
printf("%lf\n", (double)SSS[0]);
printf("%lf\n", (double)(S[0]-'0'));
printf("%d\n",(int)((double)(S[0]-'0')));
return 0;
}
#gcc...
# ./a.out
sizeof(double):8
sizeof((S[0]-'0')):4
sizeof(char):1
-48.000000
-48.000000
-48
#
This is what I was talking about.... A better approach would be to use
proper library transforms instead of type-casting...
Igor M-)
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