A colleague of mine seems to have found the answer for me. Even though
it doesn't make sense, the error appears to support ANSI. There is
a discussion at:
www.egr.unlv.edu/~ftlofaro/computers/ansi-bogosity.txt
-jeffp
> Actually, I've reviewed this a little more closely, and found
> one difference that may be significant, even though it
> shouldn't be. My code is actually:
>
> void MyCall(const char ** x);
>
> void my_fun()
> {
> char myPointer[50];
>
> ...
>
> MyCall(&myPointer);
> ...
>
> return;
> }
>
> I'm passing a pointer to a char *. Does anyone
> know why the compiler fails this?
>
>
> > This thread was opened a long time ago, but I hit an issue
> > related to it today--this thread is the closest I could find
> > in the archives:
> >
> > >> ... I have an API call which requires a const char *x,
> > >> how do I pass the variable myString in the function call ...
> > >
> > > hehe.. this dont work?
> > >
> > > APICall( (const char *) myPointer );
> > >
> > > ???
> >
> > Why is the "const" in "(const char *)" needed?
> >
> > basically, what I want to do is:
> >
> > void APICall(const char * x);
> >
> > void my_fun()
> > {
> > char myPointer[50];
> >
> > ...
> >
> > APICall(myPointer);
> >
> > ...
> >
> > return;
> > }
> >
> >
> > I understand that the reverse would be true--I shouldn't pass a
> > const char * to a routine that would modify it, but in this case
> > I'm passing a char * to a routine that is basically promising not
> > to modify it--but APIcall() doesn't really care if the variable passed
> > in is const or not.
> >
> > I've got code like this all over in CW R6 that worked fine (and also
> > on other compilers, too), but now I get compiler errors in CW R7.
> > Is there a way to turn off that error?
> >
> >
> > thanks
> >
> > Jeff Pahren
> > Franklin Electronic Publishers, Inc.
> >
> >
> >
> >
> > --
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> >
>
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